兔子再生计数.(斐波那契数列问题)

# 斐波那契数列:https://www.python.org/ def fib(n):     a, b = 0, 1     s=0     while a < n:         print(a , end=' ')         a, b = b, a+b     print() fib(8)

i,num,n1,n2=1,1,0,0 while i<=8:     if i==1:         print("第一个月：有%d对" %num)         n1=num     elif i==2:         print("第二个月:有%d对" %num)         n2=num

    else:         num=n1+n2         # print("第%i个月兔子有%d对" %(i,num))         print('第{}个月有{}对兔子.'.format(i,num))         n2=n1         n1=num     i+=1

# 递归做法 def jc (n):     if n <= 2:         return 1     return jc(n-1) + jc(n-2) print('共有{}对兔子'.format(jc(8)))